Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

A. 2 times B. 2  1 times 2 C. 2  3 times 4 D. 3 times Answer: Option A Explanation: Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years. (4x + 8) = 5 (x + 8) 2  8x + 16 = 5x + 40  3x = 24  x = 8. Hence, required ratio = (4x + 16) = 48 = 2. (x + 16) 24